-0.017x^2+1.08x+5.6=0

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Solution for -0.017x^2+1.08x+5.6=0 equation: 



-0.017x^2+1.08x+5.6=0

a = -0.017; b = 1.08; c = +5.6;
Δ = b2-4ac
Δ = 1.082-4·(-0.017)·5.6
Δ = 1.5472
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.08)-\sqrt{1.5472}}{2*-0.017}=\frac{-1.08-\sqrt{1.5472}}{-0.034}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.08)+\sqrt{1.5472}}{2*-0.017}=\frac{-1.08+\sqrt{1.5472}}{-0.034}
$

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